Month-to-date through today-2 for last year

if this gives me the right answer for mtd through today-2 for this year (3/1/2020 through 3/22/2020), how do i get the same thing for last year?

if ( dt >= start_of_month ( today ( ) ) and dt <= add_days ( today ( ) , -2 ) ) then [column] else null 

that is, if today is 3/24/2020 i need a formula to give me 3/1/2019 through 3/22/2019

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